There were two Mizbe’chos (Altars) in The Mishkan (Tabernacle). The Outer Mizbe’ach is five amos (cubits) long (see A), five amos wide (see B), and three amos high (see C) [Shemos (Exodus) 38:1]. Rabbi Yehudah takes these measurements literally. Rabbi Yose says that the Outer Mizbe’ach is actually twice as high as it is long [Rashi on Shemos 27:1]. What is the difference in heights between the two opinions?
By Rabbi Yehudah C = 3 amos
By Rabbi Yose C = 2A = 10 amos
The difference is 10 – 3 = 7 amos